1897 Iowa Gubernatorial Election
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1897 Iowa Gubernatorial Election
1897 Iowa gubernatorial election

← 1895 November 2, 1897 1899 →
  Leslie Shaw, Bain photo portrait.jpg No image.svg
Nominee L. M. Shaw Frederick Edward White
Party Republican Democratic
Popular vote 224,729 194,853
Percentage 51.27% 44.46%

Governor before election

Francis M. Drake

Elected Governor

L. M. Shaw

The 1897 Iowa gubernatorial election was held on November 2, 1897. Republican nominee L. M. Shaw defeated Democratic nominee Frederick Edward White with 51.27% of the vote.

General election


Major party candidates

  • L. M. Shaw, Republican
  • Frederick Edward White, Democratic

Other candidates

  • S. P. Leland, Prohibition
  • Charles Lloyd, People's
  • John Cliggett, National Democratic
  • M. J. Kremer, Socialist Labor


1897 Iowa gubernatorial election[1]
Party Candidate Votes % ±%
Republican L. M. Shaw 224,729 51.27%
Democratic Frederick Edward White 194,853 44.46%
Prohibition S. P. Leland 8,243 1.88%
People's Charles Lloyd 5,295 1.21%
Independent John Cliggett 4,296 0.98%
Socialist Labor M. J. Kremer 876 0.20%
Majority 29,876
Republican hold Swing


  1. ^ Kalb, Deborah (24 December 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved 2020.

  This article uses material from the Wikipedia page available here. It is released under the Creative Commons Attribution-Share-Alike License 3.0.



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