1904 United States Presidential Election in Delaware
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1904 United States Presidential Election in Delaware
United States presidential election in Delaware, 1904

← 1900 November 8, 1904 1908 →
  President Roosevelt - Pach Bros.tif AltonBParker.png
Nominee Theodore Roosevelt Alton B. Parker
Party Republican Democratic
Home state New York New York
Running mate Charles W. Fairbanks Henry G. Davis
Electoral vote 3 0
Popular vote 23,705 19,347
Percentage 54.05% 44.11%

President before election

Theodore Roosevelt
Republican

Elected President

Theodore Roosevelt
Republican

The 1904 United States presidential election in Delaware took place on November 8, 1904. All contemporary 45 states were part of the 1904 United States presidential election. Delaware voters chose three electors to the Electoral College, which selected the president and vice president.

Delaware was won by the Republican nominees, incumbent President Theodore Roosevelt of New York and his running mate Charles W. Fairbanks of Indiana.

Results

United States presidential election in Delaware, 1904[1]
Party Candidate Votes Percentage Electoral votes
Republican Theodore Roosevelt 23,705 54.05% 3
Democratic Alton B. Parker 19,347 44.11% 0
Prohibition Silas C. Swallow 607 1.38% 0
Social Democratic Eugene Debs 146 0.33% 0
Populist Thomas E. Watson 51 0.12% 0
Totals 43,856 100.00% 3
Voter turnout --

References

  1. ^ Dave Leip's U.S. Election Atlas; Presidential General Election Results - Delaware

Notes


  This article uses material from the Wikipedia page available here. It is released under the Creative Commons Attribution-Share-Alike License 3.0.

1904_United_States_presidential_election_in_Delaware
 



 



 
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