1918 Iowa Gubernatorial Election
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1918 Iowa Gubernatorial Election
1918 Iowa gubernatorial election

← 1916 November 5, 1918 1920 →
  William Lloyd Harding in 1915.jpg ClaudeRPorter.jpg
Nominee William L. Harding Claude R. Porter
Party Republican Democratic
Popular vote 192,662 178,815
Percentage 50.55% 46.92%

Governor before election

William L. Harding
Republican

Elected Governor

William L. Harding
Republican

The 1918 Iowa gubernatorial election was held on November 5, 1918. Republican nominee William L. Harding defeated Democratic nominee Claude R. Porter with 50.55% of the vote.

General election

Candidates

Major party candidates

  • William L. Harding, Republican
  • Claude R. Porter, Democratic

Other candidates

  • Andrew Engle, Socialist
  • M. L. Christian, Prohibition

Results

1918 Iowa gubernatorial election[1]
Party Candidate Votes % ±%
Republican William L. Harding 192,662 50.55%
Democratic Claude R. Porter 178,815 46.92%
Socialist Andrew Engle 8,005 2.10%
Prohibition M. L. Christian 1,625 0.43%
Majority 13,847
Turnout
Republican hold Swing

References

  1. ^ "Guide to U.S. Elections". Retrieved 2020.

  This article uses material from the Wikipedia page available here. It is released under the Creative Commons Attribution-Share-Alike License 3.0.

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