1918 Iowa Gubernatorial Election
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1918 Iowa Gubernatorial Election
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The 1918 Iowa gubernatorial election was held on November 5, 1918. Republican nominee William L. Harding defeated Democratic nominee Claude R. Porter with 50.55% of the vote.
General election
Candidates
Major party candidates
- William L. Harding, Republican
- Claude R. Porter, Democratic
Other candidates
- Andrew Engle, Socialist
- M. L. Christian, Prohibition
Results
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Republican | William L. Harding | 192,662 | 50.55% | ||
| Democratic | Claude R. Porter | 178,815 | 46.92% | ||
| Socialist | Andrew Engle | 8,005 | 2.10% | ||
| Prohibition | M. L. Christian | 1,625 | 0.43% | ||
| Majority | 13,847 | ||||
| Turnout | |||||
| Republican hold | Swing | ||||
References
- ^ "Guide to U.S. Elections". Retrieved 2020.
This article uses material from the Wikipedia page available here. It is released under the Creative Commons Attribution-Share-Alike License 3.0.
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