1920 Iowa Gubernatorial Election
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1920 Iowa Gubernatorial Election
1920 Iowa gubernatorial election

← 1918 November 2, 1920 1922 →
  Nathan E. Kendall.png Clyde Herring (cropped).jpg
Nominee Nathan E. Kendall Clyde L. Herring
Party Republican Democratic
Popular vote 513,118 338,108
Percentage 58.66% 38.65%

Governor before election

William L. Harding

Elected Governor

Nathan E. Kendall

The 1920 Iowa gubernatorial election was held on November 2, 1920. Republican nominee Nathan E. Kendall defeated Democratic nominee Clyde L. Herring with 58.66% of the vote.

General election


Major party candidates

  • Nathan E. Kendall, Republican
  • Clyde L. Herring, Democratic

Other candidates

  • George J. Peck, Socialist
  • Mathis Faber, Farmer-Labor
  • J. Jay Hisel, Socialist Labor


1920 Iowa gubernatorial election[1]
Party Candidate Votes % ±%
Republican Nathan E. Kendall 513,118 58.66%
Democratic Clyde L. Herring 338,108 38.65%
Socialist George J. Peck 13,671 1.56%
Farmer-Labor Mathis Faber 9,153 1.05%
Socialist Labor J. Jay Hisel 760 0.09%
Majority 175,010
Republican hold Swing


  1. ^ Kalb, Deborah (24 December 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved 2020.

  This article uses material from the Wikipedia page available here. It is released under the Creative Commons Attribution-Share-Alike License 3.0.



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