1920 Iowa Gubernatorial Election
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1920 Iowa Gubernatorial Election
1920 Iowa gubernatorial election

← 1918 November 2, 1920 1922 →
  Nathan E. Kendall.png Clyde Herring (cropped).jpg
Nominee Nathan E. Kendall Clyde L. Herring
Party Republican Democratic
Popular vote 513,118 338,108
Percentage 58.66% 38.65%

Governor before election

William L. Harding
Republican

Elected Governor

Nathan E. Kendall
Republican

The 1920 Iowa gubernatorial election was held on November 2, 1920. Republican nominee Nathan E. Kendall defeated Democratic nominee Clyde L. Herring with 58.66% of the vote.

General election

Candidates

Major party candidates

  • Nathan E. Kendall, Republican
  • Clyde L. Herring, Democratic

Other candidates

  • George J. Peck, Socialist
  • Mathis Faber, Farmer-Labor
  • J. Jay Hisel, Socialist Labor

Results

1920 Iowa gubernatorial election[1]
Party Candidate Votes % ±%
Republican Nathan E. Kendall 513,118 58.66%
Democratic Clyde L. Herring 338,108 38.65%
Socialist George J. Peck 13,671 1.56%
Farmer-Labor Mathis Faber 9,153 1.05%
Socialist Labor J. Jay Hisel 760 0.09%
Majority 175,010
Turnout
Republican hold Swing

References

  1. ^ Kalb, Deborah (24 December 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved 2020.

  This article uses material from the Wikipedia page available here. It is released under the Creative Commons Attribution-Share-Alike License 3.0.

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