Capstan Equation
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Capstan Equation
An example of when knowledge of the capstan equation might have been useful. The bent white tube contains a cord to raise and lower a curtain. The tube is bent some 40 degrees in two places. The blue line indicates a more efficient design.
An example of holding capstans and a powered capstan used to raise sails on a tall ship.

The capstan equation or belt friction equation, also known as Eytelwein's formula,[1][2] relates the hold-force to the load-force if a flexible line is wound around a cylinder (a bollard, a winch or a capstan).[3][2]

Because of the interaction of frictional forces and tension, the tension on a line wrapped around a capstan may be different on either side of the capstan. A small holding force exerted on one side can carry a much larger loading force on the other side; this is the principle by which a capstan-type device operates.

A holding capstan is a ratchet device that can turn only in one direction; once a load is pulled into place in that direction, it can be held with a much smaller force. A powered capstan, also called a winch, rotates so that the applied tension is multiplied by the friction between rope and capstan. On a tall ship a holding capstan and a powered capstan are used in tandem so that a small force can be used to raise a heavy sail and then the rope can be easily removed from the powered capstan and tied off.

In rock climbing with so-called top-roping, a lighter person can hold (belay) a heavier person due to this effect.

The formula is

${\displaystyle T_{\text{load}}=T_{\text{hold}}\ e^{\mu \phi }~,}$

where ${\displaystyle T_{\text{load}}}$ is the applied tension on the line, ${\displaystyle T_{\text{hold}}}$ is the resulting force exerted at the other side of the capstan, ${\displaystyle \mu }$ is the coefficient of friction between the rope and capstan materials, and ${\displaystyle \phi }$ is the total angle swept by all turns of the rope, measured in radians (i.e., with one full turn the angle ${\displaystyle \phi =2\pi \,}$).

Several assumptions must be true for the formula to be valid:

1. The rope is on the verge of full sliding, i.e. ${\displaystyle T_{\text{load}}}$ is the maximum load that one can hold. Smaller loads can be held as well, resulting in a smaller effective contact angle ${\displaystyle \phi }$.
2. It is important that the line is not rigid, in which case significant force would be lost in the bending of the line tightly around the cylinder. (The equation must be modified for this case.) For instance a Bowden cable is to some extent rigid and doesn't obey the principles of the Capstan equation.
3. The line is non-elastic.

It can be observed that the force gain increases exponentially with the coefficient of friction, the number of turns around the cylinder, and the angle of contact. Note that the radius of the cylinder has no influence on the force gain.

The table below lists values of the factor ${\displaystyle e^{\mu \phi }\,}$ based on the number of turns and coefficient of friction ?.

Number
of turns
Coefficient of friction ?
0.1 0.2 0.3 0.4 0.5 0.6 0.7
1 1.9 3.5 6.6 12 23 43 81
2 3.5 12 43 152 535 1881 6661
3 6.6 43 286 1881 12392 81612 437503
4 12 152 1881 23228 286751 3540026 43702631
5 23 535 12392 286751 6635624 153552935 3553321281

From the table it is evident why one seldom sees a sheet (a rope to the loose side of a sail) wound more than three turns around a winch. The force gain would be extreme besides being counter-productive since there is risk of a riding turn, result being that the sheet will foul, form a knot and not run out when eased (by slacking grip on the tail (free end)).

It is both ancient and modern practice for anchor capstans and jib winches to be slightly flared out at the base, rather than cylindrical, to prevent the rope (anchor warp or sail sheet) from sliding down. The rope wound several times around the winch can slip upwards gradually, with little risk of a riding turn, provided it is tailed (loose end is pulled clear), by hand or a self-tailer.

For instance, the factor "153,552,935" (5 turns around a capstan with a coefficient of friction of 0.6) means, in theory, that a newborn baby would be capable of holding (not moving) the weight of two USS Nimitz supercarriers (97,000 tons each, but for the baby it would be only a little more than 1 kg).[] The large number of turns around the capstan combined with such a high friction coefficient mean that very little additional force is necessary to hold such heavy weight in place. The cables necessary to support this weight, as well as the capstan's ability to withstand the crushing force of those cables, are separate considerations.

## Derivation of the capstan equation

Forces between a rope and capstan

The first step is to relate the radial or normal force ${\displaystyle F_{N}}$(Newtons/radian) at any point of the rope wrapped around a capstan to the tension ${\displaystyle T}$(Newtons) in the rope as shown in the figure. The y axis component of the upward force of the capstan on the rope, ${\displaystyle F_{N}}$, must equal the Y axis downward component of the tension in the rope, ${\displaystyle T_{\text{load}}\sin(\varphi )}$.

${\displaystyle F_{N}=T_{\text{load}}\sin(\varphi )}$

In the limit as ${\displaystyle \varphi }$ goes to zero (the small-angle approximation), ${\displaystyle \sin(d\varphi )=d\varphi }$ and ${\displaystyle T_{\text{hold}}=T_{\text{load}}=T}$

${\displaystyle dF_{N}=Td\varphi }$

So the frictional force over a wrap angle ${\displaystyle d\varphi }$ is

${\displaystyle dF_{f}=\mu {dF_{N}}=\mu {T}d\varphi }$ where ${\displaystyle \mu }$ is the coefficient of friction (nonslip).

The increase in rope tension ${\displaystyle dT}$ over a wrap angle ${\displaystyle d\varphi }$ is the frictional force over that angle so

${\displaystyle dT=\mu {T}d\varphi =dF_{f}}$
${\displaystyle {\frac {1}{T}}dT=\mu d\varphi }$

Integration of both sides yields

${\displaystyle \int _{T_{\text{hold}}}^{T_{\text{load}}}{\frac {1}{T}}\;{dT}=\int _{0}^{\phi }\mu \;{d}\varphi }$
${\displaystyle \ln T_{\text{load}}-\ln T_{\text{hold}}=\ln {\frac {T_{\text{load}}}{T_{\text{hold}}}}=\mu \phi }$

and exponentiating both sides,

${\displaystyle {\frac {T_{\text{load}}}{T_{\text{hold}}}}={e}^{\mu \phi }}$

Finally,

${\displaystyle T_{\text{load}}=T_{\text{hold}}{e}^{\mu \phi }}$

## Generalization of the Capstan equation for a V-belt

The belt friction equation for a v-belt is:

${\displaystyle T_{\text{load}}=T_{\text{hold}}{e}^{\mu \phi /\sin(\alpha /2)}}$

where ${\displaystyle \alpha }$ is the angle (in radians) between the two flat sides of the pulley that the v-belt presses against.[4] A flat belt has an effective angle of ${\displaystyle \alpha =\pi }$.

The material of a v-belt or multi-v serpentine belt tends to wedge into the mating groove in a pulley as the load increases, improving torque transmission.[5]

For the same power transmission, a V-belt requires less tension than a flat belt, increasing bearing life.[4]

## Generalization of the Capstan equation for a rope lying on an arbitrary orthotropic surface

If a rope is lying in equilibrium under tangential forces on a rough orthotropic surface then all three following conditions are satisfied:

1. No separation - normal reaction ${\displaystyle N}$ is positive for all points of the rope curve:
${\displaystyle N=-k_{n}T>0}$, where ${\displaystyle k_{n}}$ is a normal curvature of the rope curve.
2. Dragging coefficient of friction ${\displaystyle \mu _{g}}$ and angle ${\displaystyle \alpha }$ are satisfying the following criteria for all points of the curve
${\displaystyle -\mu _{g}<\tan \alpha <+\mu _{g}}$
3. Limit values of the tangential forces:
The forces at both ends of the rope ${\displaystyle T}$ and ${\displaystyle T_{0}}$ are satisfying the following inequality
${\displaystyle T_{0}e^{-\int _{s}\omega ds}\leq T\leq T_{0}e^{\int _{s}\omega ds}}$
with ${\displaystyle \omega =\mu _{\tau }{\sqrt {k_{n}^{2}-{\frac {k_{g}^{2}}{\mu _{g}^{2}}}}}=\mu _{\tau }k{\sqrt {\cos ^{2}\alpha -{\frac {\sin ^{2}\alpha }{\mu _{g}^{2}}}}}}$,
where ${\displaystyle k_{g}}$is a geodesic curvature of the rope curve, ${\displaystyle k}$ is a curvature of a rope curve, ${\displaystyle \mu _{\tau }}$is a coefficient of friction in the tangential direction.
If ${\displaystyle \omega =const}$ then ${\displaystyle T_{0}e^{-\mu _{\tau }ks\,{\sqrt {\cos ^{2}\alpha -{\frac {\sin ^{2}\alpha }{\mu _{g}^{2}}}}}}\leq T\leq T_{0}e^{\mu _{\tau }ks\,{\sqrt {\cos ^{2}\alpha -{\frac {\sin ^{2}\alpha }{\mu _{g}^{2}}}}}}}$.

This generalization has been obtained by Konyukhov,[6][7]

## References

1. ^ Mann, Herman (5 May 2005). "Belt Friction". Archived from the original on 2007-08-02. Retrieved .
2. ^ a b Attaway, Stephen W. (1999). The Mechanics of Friction in Rope Rescue (PDF). International Tech Rescue Symposium. Archived from the original (PDF) on August 21, 2010. Retrieved 2010.
3. ^ Johnson, K. L. (1985). Contact Mechanics (PDF). Retrieved 2011.
4. ^ a b Moradmand, Jamshid; Marcks, Russell; Looker, Tom. "Belt and Wrap Friction" (PDF).
5. ^ Slocum, Alexander (2008). "FUNdaMENTALS of Design" (PDF). page 5-9.
6. ^ Konyukhov, Alexander (2015-04-01). "Contact of ropes and orthotropic rough surfaces". Journal of Applied Mathematics and Mechanics. 95 (4): 406-423. Bibcode:2015ZaMM...95..406K. doi:10.1002/zamm.201300129. ISSN 1521-4001.
7. ^ Konyukhov, A.; Izi, R. "Introduction to Computational Contact Mechanics: A Geometrical Approach". Wiley.

• Arne Kihlberg, Kompendium i Mekanik för E1, del II, Göteborg 1980, 60-62.