First Inauguration of Grover Cleveland
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First Inauguration of Grover Cleveland
First Presidential Inauguration of Grover Cleveland
Cleveland Inauguration 1885.jpg
Cleveland delivering his inaugural address.
DateMarch 4, 1885; 134 years ago (1885-03-04)
LocationWashington, D.C.
United States Capitol
ParticipantsPresident Grover Cleveland
Vice President Thomas A. Hendricks

The first inauguration of Grover Cleveland as the 22nd President of the United States was held on Wednesday, March 4, 1885, at the eastern portico of the United States Capitol in Washington, D.C.. The inauguration marked the commencement of the first four-year term of Grover Cleveland as President and the only term of Thomas A. Hendricks as Vice President. Hendricks died 266 days into this term, and the office remained vacant for the balance of it. (Prior to ratification of the Twenty-fifth Amendment in 1967, no constitutional provision existed for filling an intra-term vacancy in the vice presidency.)

Chief Justice Morrison R. Waite administered the presidential oath of office, and Cleveland held a Bible given to him at age 15 by his mother as he recited it. Cleveland's second inauguration took place eight years after the first, as his two terms in office were not consecutive. He is the only U.S. president to serve non-consecutive terms.[1]

See also

References

  1. ^ "Archived copy". Archived from the original on 2009-01-20. Retrieved .CS1 maint: Archived copy as title (link)

External links


  This article uses material from the Wikipedia page available here. It is released under the Creative Commons Attribution-Share-Alike License 3.0.

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